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Uploaded prob 231
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WHAHA-HA committed Jul 4, 2020
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13 changes: 13 additions & 0 deletions Problems/231.txt
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PROBLEM 231:

Given a string with repeated characters, rearrange the string so that no two adjacent characters are the same.
If this is not possible, return None.


EXAMPLE:

Input = "aaabbc"
Output = "ababac"

Input = "aaab"
Output = None
69 changes: 69 additions & 0 deletions Solutions/231.py
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'''
Problem:
Given a string with repeated characters, rearrange the string so that no two adjacent characters are the same.
If this is not possible, return None.
Example:
Input = "aaabbc"
Output = "ababac"
Input = "aaab"
Output = None
'''

def get_unique_adjacent(string):
length = len(string)
freq = {}

if (length == 0): return string

# getting the character frequency
for i in range(length):
if (string[i] in freq): freq[string[i]] += 1
else: freq[string[i]] = 1

sorted_freq = sorted(freq.items(), key=lambda x: x[1], reverse=True)
queue = list(sorted_freq)

# checking if a desired string can be formed
if (length % 2 == 0):
if (sorted_freq[0][1] > length // 2): return None
else:
if (sorted_freq[0][1] > (length // 2) + 1): return None

res = ""

# creating the required string
while (queue):
if (len(queue) == 1):
if (queue[0][1] == 2):
res = queue[0][0] + res + queue[0][0]
break
elif (queue[0][1] == 1):
if (res[-1] != queue[0][0]): res += queue[0][0]
else: res = queue[0][0] + res
break
else:
return None

res += queue[0][0] + queue[1][0]

queue[0] = queue[0][0], queue[0][1]-1
queue[1] = queue[1][0], queue[1][1]-1

if (len(queue) > 1 and queue[1][1] == 0): queue.pop(1)
if (len(queue) > 0 and queue[0][1] == 0): queue.pop(0)

return res


# DRIVER CODE
print(get_unique_adjacent("aaabbc"))
print(get_unique_adjacent("aaabbcc"))
print(get_unique_adjacent("aaabbac"))

# cannot form a word of the desired form
print(get_unique_adjacent("aaab"))
print(get_unique_adjacent("aaabbaa"))

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