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Yutong-gannis authored Jan 16, 2023
1 parent c029cf8 commit 8993715
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259 changes: 259 additions & 0 deletions Control/controllers/MPC_controller.py
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import matplotlib.pyplot as plt
import numpy as np
from math import *
from cvxopt import matrix, solvers


class MPC:
def __init__(self):
self.Np = 60 # 预测步长
self.Nc = 60 # 控制步长

self.dt = 0.1 # 时间间隔
self.Length = 1.0 # 车辆轴距

max_steer = 30 * pi / 180 # 最大方向盘打角
max_steer_v = 15 * pi / 180 # 最大方向盘打角速度
max_v = 8.7 # 最大车速
max_a = 1.0 # 最大加速度

# 目标函数相关矩阵
self.Q = 50 * np.identity(3 * self.Np) # 位姿权重
self.R = 100 * np.identity(2 * self.Nc) # 控制权重

self.kesi = np.zeros((5, 1))

self.A = np.identity(5)

self.B = np.block([
[np.zeros((3, 2))],
[np.identity(2)]
])

self.C = np.block([
[np.identity(3), np.zeros((3, 2))]
])

self.PHI = np.zeros((3 * self.Np, 5))
self.THETA = np.zeros((3 * self.Np, 2 * self.Nc))

self.CA = (self.Np + 1) * [self.C]

self.H = np.zeros((2 * self.Nc, 2 * self.Nc))

self.f = np.zeros((2 * self.Nc, 1))

# 不等式约束相关矩阵
A_t = np.zeros((self.Nc, self.Nc))
for p in range(self.Nc):
for q in range(p + 1):
A_t[p][q] = 1

A_I = np.kron(A_t, np.identity(2))

# 控制量约束
umin = np.array([[-max_v], [-max_steer]])
umax = np.array([[max_v], [max_steer]])
self.Umin = np.kron(np.ones((self.Nc, 1)), umin)
self.Umax = np.kron(np.ones((self.Nc, 1)), umax)

# 控制增量约束
delta_umin = np.array([[-max_a * self.dt], [-max_steer_v * self.dt]])
delta_umax = np.array([[max_a * self.dt], [max_steer_v * self.dt]])
delta_Umin = np.kron(np.ones((self.Nc, 1)), delta_umin)
delta_Umax = np.kron(np.ones((self.Nc, 1)), delta_umax)

self.A_cons = np.zeros((2 * 2 * self.Nc, 2 * self.Nc))
self.A_cons[0:2 * self.Nc, 0:2 * self.Nc] = A_I
self.A_cons[2 * self.Nc:4 * self.Nc, 0:2 * self.Nc] = np.identity(2 * self.Nc)

self.lb_cons = np.zeros((2 * 2 * self.Nc, 1))
self.lb_cons[2 * self.Nc:4 * self.Nc, 0:1] = delta_Umin

self.ub_cons = np.zeros((2 * 2 * self.Nc, 1))
self.ub_cons[2 * self.Nc:4 * self.Nc, 0:1] = delta_Umax

def mpcControl(self, x, y, yaw, v, angle, tar_x, tar_y, tar_yaw, tar_v, tar_angle): # mpc优化控制
T = self.dt
L = self.Length

# 更新误差
self.kesi[0][0] = x - tar_x
self.kesi[1][0] = y - tar_y
self.kesi[2][0] = self.normalizeTheta(yaw - tar_yaw)
self.kesi[3][0] = v - tar_v
self.kesi[4][0] = angle - tar_angle

# 更新A矩阵
self.A[0][2] = -tar_v * sin(tar_yaw) * T
self.A[0][3] = cos(tar_yaw) * T
self.A[1][2] = tar_v * cos(tar_yaw) * T
self.A[1][3] = sin(tar_yaw) * T
self.A[2][3] = tan(tar_angle) * T / L
self.A[2][4] = tar_v * T / (L * (cos(tar_angle) ** 2))

# 更新B矩阵
self.B[0][0] = cos(tar_yaw) * T
self.B[1][0] = sin(tar_yaw) * T
self.B[2][0] = tan(tar_angle) * T / L
self.B[2][1] = tar_v * T / (L * (cos(tar_angle) ** 2))

# 更新CA
for i in range(1, self.Np + 1):
self.CA[i] = np.dot(self.CA[i - 1], self.A)

# 更新PHI和THETA
for j in range(self.Np):
self.PHI[3 * j:3 * (j + 1), 0:5] = self.CA[j + 1]
for k in range(min(self.Nc, j + 1)):
self.THETA[3 * j:3 * (j + 1), 2 * k: 2 * (k + 1)
] = np.dot(self.CA[j - k], self.B)

# 更新H
self.H = np.dot(np.dot(self.THETA.transpose(), self.Q),
self.THETA) + self.R

# 更新f
self.f = 2 * np.dot(np.dot(self.THETA.transpose(), self.Q),
np.dot(self.PHI, self.kesi))

# 更新约束
Ut = np.kron(np.ones((self.Nc, 1)), np.array([[v], [angle]]))
self.lb_cons[0:2 * self.Nc, 0:1] = self.Umin - Ut
self.ub_cons[0:2 * self.Nc, 0:1] = self.Umax - Ut

# 求解QP
P = matrix(self.H)
q = matrix(self.f)
G = matrix(np.block([
[self.A_cons],
[-self.A_cons]
]))
h = matrix(np.block([
[self.ub_cons],
[-self.lb_cons]
]))

solvers.options['show_progress'] = False
sol = solvers.qp(P, q, G, h)
X = sol['x']

# 输出结果
v += X[0]
angle += X[1]

return v, angle

def normalizeTheta(self, angle): # 角度归一化
while (angle >= pi):
angle -= 2 * pi

while (angle < -pi):
angle += 2 * pi

return angle

def findIdx(self, x, y, cx, cy): # 寻找欧式距离最近的点
min_dis = float('inf')
idx = 0

for i in range(len(cx)):
dx = x - cx[i]
dy = y - cy[i]
dis = dx ** 2 + dy ** 2
if (dis < min_dis):
min_dis = dis
idx = i

return idx

def update(self, x, y, yaw, v, angle): # 模拟车辆位置
x += v * cos(yaw) * self.dt
y += v * sin(yaw) * self.dt
yaw += v / self.Length * tan(angle) * self.dt

return x, y, yaw

import time
if __name__ == '__main__':
cx = np.linspace(0, 200, 20)
cy = np.zeros(len(cx))
dx = np.zeros(len(cx))
ddx = np.zeros(len(cy))
cyaw = np.zeros(len(cx))
ck = np.zeros(len(cx))

for i in range(len(cx)):
cy[i] = cos(cx[i] / 10) * cx[i] / 10

# 计算一阶导数
for i in range(len(cx) - 1):
dx[i] = (cy[i + 1] - cy[i]) / (cx[i + 1] - cx[i])
dx[len(cx) - 1] = dx[len(cx) - 2]

# 计算二阶导数
for i in range(len(cx) - 2):
ddx[i] = (cy[i + 2] - 2 * cy[i + 1] + cy[i]) / (0.5 * (cx[i + 2] - cx[i])) ** 2
ddx[len(cx) - 2] = ddx[len(cx) - 3]
ddx[len(cx) - 1] = ddx[len(cx) - 2]

# 计算偏航角
for i in range(len(cx)):
cyaw[i] = atan(dx[i])

# 计算曲率
for i in range(len(cx)):
ck[i] = ddx[i] / (1 + dx[i] ** 2) ** 1.5

# 初始状态
x = 0.0
y = 5.0
yaw = 0.0
v = 0.0
angle = 0.0
t = 0

# 历史状态
xs = [x]
ys = [y]
vs = [v]
angles = [angle]
ts = [t]

# 实例化
mpc = MPC()

while (1):
time_start = time.time()
idx = mpc.findIdx(x, y, cx, cy)
if (idx == len(cx) - 1):
break

tar_v = 30.0 / 3.6
tar_angle = atan(mpc.Length * ck[idx])

(v, angle) = mpc.mpcControl(x, y, yaw, v, angle,
cx[idx], cy[idx], cyaw[idx], tar_v, tar_angle)

(x, y, yaw) = mpc.update(x, y, yaw, v, angle)
print(time.time() - time_start)
# 保存状态
xs.append(x)
ys.append(y)
vs.append(v)
angles.append(angle)
t = t + 0.1
ts.append(t)

# 显示
plt.plot(cx, cy)
plt.scatter(xs, ys, c='r', marker='*')
plt.pause(0.01) # 暂停0.01秒
plt.clf()

plt.close()
plt.subplot(2, 1, 1)
plt.plot(ts, vs)
plt.subplot(2, 1, 2)
plt.plot(ts, angles)
plt.show()
28 changes: 28 additions & 0 deletions Control/controllers/PID_controller.py
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import numpy as np
import copy


class PID:
def __init__(self, kp, ki, kd):
self.kp = kp
self.ki = ki
self.kd = kd
self.ep = 0.0
self.ei = 0.0
self.ed = 0.0
self.dt = 0.1

def update_e(self, e):
self.ed = e - self.ep
self.ei += e
self.ep = copy.deepcopy(e)

def get_u(self):
u = self.kp * self.ep + self.ki * self.ei + self.kd * self.ed
if u > np.pi / 6: u = np.pi / 6
if u < -np.pi / 6: u = -np.pi / 6
return u

def get_a(self):
a = self.kp * self.ep + self.ki * self.ei + self.kd * self.ed
return -a
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