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220 changes: 220 additions & 0 deletions data_structures/LazyPropogation/LazySegmentTree.java
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// Java program to demonstrate lazy propagation in segment tree
class LazySegmentTree
{
final int MAX = 1000; // Max tree size
int tree[] = new int[MAX]; // To store segment tree
int lazy[] = new int[MAX]; // To store pending updates

/* si -> index of current node in segment tree
ss and se -> Starting and ending indexes of elements for
which current nodes stores sum.
us and eu -> starting and ending indexes of update query
ue -> ending index of update query
diff -> which we need to add in the range us to ue */
void updateRangeUtil(int si, int ss, int se, int us,
int ue, int diff)
{
// If lazy value is non-zero for current node of segment
// tree, then there are some pending updates. So we need
// to make sure that the pending updates are done before
// making new updates. Because this value may be used by
// parent after recursive calls (See last line of this
// function)
if (lazy[si] != 0)
{
// Make pending updates using value stored in lazy
// nodes
tree[si] += (se - ss + 1) * lazy[si];

// checking if it is not leaf node because if
// it is leaf node then we cannot go further
if (ss != se)
{
// We can postpone updating children we don't
// need their new values now.
// Since we are not yet updating children of si,
// we need to set lazy flags for the children
lazy[si * 2 + 1] += lazy[si];
lazy[si * 2 + 2] += lazy[si];
}

// Set the lazy value for current node as 0 as it
// has been updated
lazy[si] = 0;
}

// out of range
if (ss > se || ss > ue || se < us)
return;

// Current segment is fully in range
if (ss >= us && se <= ue)
{
// Add the difference to current node
tree[si] += (se - ss + 1) * diff;

// same logic for checking leaf node or not
if (ss != se)
{
// This is where we store values in lazy nodes,
// rather than updating the segment tree itelf
// Since we don't need these updated values now
// we postpone updates by storing values in lazy[]
lazy[si * 2 + 1] += diff;
lazy[si * 2 + 2] += diff;
}
return;
}

// If not completely in rang, but overlaps, recur for
// children,
int mid = (ss + se) / 2;
updateRangeUtil(si * 2 + 1, ss, mid, us, ue, diff);
updateRangeUtil(si * 2 + 2, mid + 1, se, us, ue, diff);

// And use the result of children calls to update this
// node
tree[si] = tree[si * 2 + 1] + tree[si * 2 + 2];
}

// Function to update a range of values in segment
// tree
/* us and eu -> starting and ending indexes of update query
ue -> ending index of update query
diff -> which we need to add in the range us to ue */
void updateRange(int n, int us, int ue, int diff) {
updateRangeUtil(0, 0, n - 1, us, ue, diff);
}

/* A recursive function to get the sum of values in given
range of the array. The following are parameters for
this function.
si --> Index of current node in the segment tree.
Initially 0 is passed as root is always at'
index 0
ss & se --> Starting and ending indexes of the
segment represented by current node,
i.e., tree[si]
qs & qe --> Starting and ending indexes of query
range */
int getSumUtil(int ss, int se, int qs, int qe, int si)
{
// If lazy flag is set for current node of segment tree,
// then there are some pending updates. So we need to
// make sure that the pending updates are done before
// processing the sub sum query
if (lazy[si] != 0)
{
// Make pending updates to this node. Note that this
// node represents sum of elements in arr[ss..se] and
// all these elements must be increased by lazy[si]
tree[si] += (se - ss + 1) * lazy[si];

// checking if it is not leaf node because if
// it is leaf node then we cannot go further
if (ss != se)
{
// Since we are not yet updating children os si,
// we need to set lazy values for the children
lazy[si * 2 + 1] += lazy[si];
lazy[si * 2 + 2] += lazy[si];
}

// unset the lazy value for current node as it has
// been updated
lazy[si] = 0;
}

// Out of range
if (ss > se || ss > qe || se < qs)
return 0;

// At this point sure, pending lazy updates are done
// for current node. So we can return value (same as
// was for query in our previous post)

// If this segment lies in range
if (ss >= qs && se <= qe)
return tree[si];

// If a part of this segment overlaps with the given
// range
int mid = (ss + se) / 2;
return getSumUtil(ss, mid, qs, qe, 2 * si + 1) +
getSumUtil(mid + 1, se, qs, qe, 2 * si + 2);
}

// Return sum of elements in range from index qs (query
// start) to qe (query end). It mainly uses getSumUtil()
int getSum(int n, int qs, int qe)
{
// Check for erroneous input values
if (qs < 0 || qe > n - 1 || qs > qe)
{
System.out.println("Invalid Input");
return -1;
}

return getSumUtil(0, n - 1, qs, qe, 0);
}

/* A recursive function that constructs Segment Tree for
array[ss..se]. si is index of current node in segment
tree st. */
void constructSTUtil(int arr[], int ss, int se, int si)
{
// out of range as ss can never be greater than se
if (ss > se)
return;

/* If there is one element in array, store it in
current node of segment tree and return */
if (ss == se)
{
tree[si] = arr[ss];
return;
}

/* If there are more than one elements, then recur
for left and right subtrees and store the sum
of values in this node */
int mid = (ss + se) / 2;
constructSTUtil(arr, ss, mid, si * 2 + 1);
constructSTUtil(arr, mid + 1, se, si * 2 + 2);

tree[si] = tree[si * 2 + 1] + tree[si * 2 + 2];
}

/* Function to construct segment tree from given array.
This function allocates memory for segment tree and
calls constructSTUtil() to fill the allocated memory */
void constructST(int arr[], int n)
{
// Fill the allocated memory st
constructSTUtil(arr, 0, n - 1, 0);
}


// Driver program to test above functions
public static void main(String args[])
{
int arr[] = {1, 3, 5, 7, 9, 11};
int n = arr.length;
LazySegmentTree tree = new LazySegmentTree();

// Build segment tree from given array
tree.constructST(arr, n);

// Print sum of values in array from index 1 to 3
System.out.println("Sum of values in given range = " +
tree.getSum(n, 1, 3));

// Add 10 to all nodes at indexes from 1 to 5.
tree.updateRange(n, 1, 5, 10);

// Find sum after the value is updated
System.out.println("Updated sum of values in given range = " +
tree.getSum(n, 1, 3));
}
}
// This Code is contributed by Ankur Narain Verma