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Momentum Lessons
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dmaccarthy committed Sep 7, 2024
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22 changes: 14 additions & 8 deletions docs/p30/mom/coll1d.htm
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Expand Up @@ -64,14 +64,14 @@ <h2 class="Collapse">Practice<span data-print="Practice"></span></h2><div class=
<p class="TeX">\begin{align}E_i &= \frac{1}{2}m_U{v_{iU}}^2
\\[10pt] &= \rm {\frac{1}{2} (6.65\times 10^{-27}\ kg) (6.00\times 10^7\ m/s)^2}
\\[10pt] &= \rm {1.20\times 10^{-11}\ J}
\end{align}</p>
<p>Calculate the final mechanical energy:</p>
<p class="TeX">\begin{align}E_f &= \frac{1}{2}m_P{v_{fP}}^2 + \frac{1}{2}m_U{v_{fU}}^2
\\[10pt] &= \rm {\frac{1}{2} (1.67\times 10^{-27}\ kg) (9.59\times 10^7\ m/s)^2 + \frac{1}{2} (6.65\times 10^{-27}\ kg) (3.59\times 10^7\ m/s)^2}
\\[10pt] &= \rm {1.20\times 10^{-11}\ J}
\end{align}</p>
<p>The collision appears to be elastic because the mechanical energy does not change.</p>
</div>
\end{align}</p>
<p>Calculate the final mechanical energy:</p>
<p class="TeX">\begin{align}E_f &= \frac{1}{2}m_P{v_{fP}}^2 + \frac{1}{2}m_U{v_{fU}}^2
\\[10pt] &= \rm {\frac{1}{2} (1.67\times 10^{-27}\ kg) (9.59\times 10^7\ m/s)^2 + \frac{1}{2} (6.65\times 10^{-27}\ kg) (3.59\times 10^7\ m/s)^2}
\\[10pt] &= \rm {1.20\times 10^{-11}\ J}
\end{align}</p>
<p>The collision appears to be elastic because the mechanical energy does not change.</p>
</div>
</ol></li>


Expand Down Expand Up @@ -118,6 +118,12 @@ <h2 class="Collapse">Practice<span data-print="Practice"></span></h2><div class=
<h2 class="Collapse">Review<span data-print="Review"></h2><div class="Collapse">
<div id="Review">
<ol>
<li>Define <em class="Defn">elastic</em> and <em class="Defn">inelastic</em> collisions.</li>
<div class="Answer">Elastic means that mechanical energy as well as momentum is conserved. Inelastic means that only momentum is conserved as some of the mechanical energy is transformed into non-mechanical forms such as sound or thermal energy.</div>

<li>What does it mean to say that a collision in which the objects remain attached after the collison is “completely” inelastic.</li>
<div class="Answer">The loss of mechanical energy is greatest (while momentum is conserved) when the two masses stick together.</div>

<li>A toy train set includes a locomotive of mass of 750 grams and a passenger car of mass 400 grams. The locomotive has an initial velocity of –20.0 cm/s as it backs into the passenger car which is initially at rest. The locomotive and the passenger car do not join together successfully, and the passenger car moves off with a final velocity of –15.0 cm/s. Calculate:<ol type="a">
<li>the final velocity of the locomotive.</li>
<div class="Answer">
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