Add scripting for custom property types

[dogboydog]

Aims to fix #3419

Related to #2902

Demo of the functionality so far in the console:

> for (let t of tiled.project.propertyTypes) { tiled.log( t.name) }
Breakable
Door
Enemy
KillZone
> tiled.project.findTypeByName('Enemy').name
$0 = Enemy
> tiled.project.findTypeByName('Enemy').color
$1 = #ff0000
> tiled.project.findTypeByName('Enemy').isClass
$2 = true 
> tiled.project.findTypeByName('Enemy').usageFlags  & ClassPropertyType.LayerClass
$2 = 0
> tiled.project.findTypeByName('Enemy').usageFlags  & ClassPropertyType.MapObjectClass
$3 = 4

TODO:

• Editing properties on custom types
• Adding new enum and class types to the project
• Adding new properties to class types, including properties that are classes
• Removing types from the project
• Add scripting doc

[bjorn]

It's a great start, @dogboydog! There are some open questions, especially what to do with the raw pointer and potentially whether we should rather return class members as an array (though that does seem a little clumsy and somewhat pointless since internally it's still a map for now).

[bjorn]

There's a planned feature that would enable manual ordering of class members, so it might be good to expose this as an array instead.

[dogboydog]

I'm not sure whether to make it an array in advance of that feature, but I did want to note that accessing the members through this property doesn't seem to allow adding new members and doesn't handle members of a class type (at least the last time I tried before your push)

[bjorn]

What do you mean with "doesn't handle members of a class type"? For modification we'll need setMembers or addMember, because indeed the members are returned by value here (effectively a copy).

[dogboydog]

I'd have to test again, but I think when I tested, if a member was a class, it just came back as QVariant and I couldn't do anything with it like get its name or its own nested members

[bjorn]

Hmm, you should get a PropertyValue, so it should at least have exposed its properties like typeName and value.

[dogboydog]

I'll test again when I get a chance

[dogboydog]

You're right, it's working for properties that are classes 👍

> tiled.project.findTypeByName('Class12').members['myChild'].value['hello']
$9 = false

Thanks for fixing the removal of types too . I wonder if removeTypeByName should return a boolean reflecting whether or not the type was found

[bjorn]

I wonder if this is just cause of passing by reference. The argument should either be by value or by const-reference.

[dogboydog]

Neither of those compile right now.

void setColor(QColor value) { mClassType->color = value; }

C:\Users\chris\tiled\src\tiled\scriptpropertytype.h:116: error: C2678: binary '=': no operator found which takes a left-hand operand of type 'const QColor' (or there is no acceptable conversion)

C:\Users\chris\tiled\src\tiled\scriptpropertytype.h(116): note: Conversion loses qualifiers

Or
void setColor(const QColor &value) { mClassType->color = value; }

C:\Users\chris\tiled\src\tiled\scriptpropertytype.h:116: error: C2678: binary '=': no operator found which takes a left-hand operand of type 'const QColor' (or there is no acceptable conversion)
C:\Users\chris\tiled\src\tiled\scriptpropertytype.h(116): note: Conversion loses qualifiers

[bjorn]

Ah, it's just because mClassType is a const ClassPropertyType*, so you can't modify it. You'd need a non-const ClassPropertyType*.

[bjorn]

A raw pointer is problematic here, cause there is nothing that makes sure the ScriptEnumPropertyType instance is deleted when the EnumPropertyType instance is deleted. There's a few potential solutions we can try:

• Referring to types using shared pointers, so that the wrapper object can keep the type alive.
• Adding a pointer to the ScriptEnumPropertyType from the EnumPropertyType, so that it can delete the wrapper upon destruction.
• Making a copy of the type that is owned by this wrapper. Though that means changes won't automatically apply, but we'd instead need to have a Project.addType or Project.setType to assign a modified object back to the project.
• Remembering just the name of the type and looking it up each time it is accessed (might get confusing in case the type is renamed).

I'm not sure at the moment which will be the best way forward. It depends also on the expected usage pattern of the API.

[dogboydog]

To me the first two seem like the best options. I'd prefer to retain the ability to modify a type's fields just by setting them -- I think that's simpler. So that would mean no option 3. Option 4 seems a bit messy for the reasons you mentioned (we may also want to allow renaming the types from scripting I would think, so that would be complicated by option 4)

For option 2, I guess we would have to check if there already has been a ScriptPropertyEnumType created for an EnumPropertyType before we would create a new one. Also if the main types would hold a pointer to the script wrapper, maybe they should handle creating the script wrapper themselves?

Option 1 also sounds promising but challenging for my skill set . Maybe with some pointers (ha) I could do it

[dogboydog]

So if we go for the shared pointer route, I wonder where the code for creating the shared pointers would go, maybe in PropertyTypes ? If we get that working, it would solve the const pointer issue too and allow the setters for color, drawFill, etc. to work