Completed assignment-one

02_activities/assignments/Assignment1.md

@@ -119,29 +119,108 @@ Steps to complete this part of the assignment:
 ### Write SQL
 
 #### SELECT
-1. Write a query that returns everything in the customer table.
+1. Write a query that returns everything in the customer table. 
+
+SELECT *
+FROM customer
+
+
 2. Write a query that displays all of the columns and 10 rows from the customer table, sorted by customer_last_name, then customer_first_ name.
 
+
+SELECT *
+FROM customer
+ORDER BY customer_last_name, customer_first_name
+LIMIT 10
+
+
+
 <div align="center">-</div>
 
 #### WHERE
 1. Write a query that returns all customer purchases of product IDs 4 and 9.
+
+SELECT *
+FROM customer_purchases
+WHERE product_id = 4
+OR product_id = 9
+
+
+
 2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), filtered by vendor IDs between 8 and 10 (inclusive) using either:
 	1.  two conditions using AND
+
+	SELECT *, quantity * cost_to_customer_per_qty AS price
+FROM customer_purchases
+WHERE vendor_id >= 8 AND vendor_id <= 10
+
+
 	2.  one condition using BETWEEN
 
+	SELECT *, quantity * cost_to_customer_per_qty AS price
+FROM customer_purchases
+WHERE vendor_id BETWEEN 8 AND 10
+
+
+
+
 <div align="center">-</div>
 
 #### CASE
 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. Using the product table, write a query that outputs the `product_id` and `product_name` columns and add a column called `prod_qty_type_condensed` that displays the word “unit” if the `product_qty_type` is “unit,” and otherwise displays the word “bulk.”
 
+
+SELECT 
+product_id, product_name
+,CASE WHEN product_qty_type = 'unit' THEN 'unit'
+	ELSE 'bulk'
+	END AS product_qty_type_condensed
+
+FROM product
+
+
+
 2. We want to flag all of the different types of pepper products that are sold at the market. Add a column to the previous query called `pepper_flag` that outputs a 1 if the product_name contains the word “pepper” (regardless of capitalization), and otherwise outputs 0.
 
+
+SELECT 
+product_id, product_name
+,CASE WHEN product_qty_type = 'unit' THEN 'unit'
+	ELSE 'bulk'
+	END AS product_qty_type_condensed
+	,CASE WHEN product_name like '%pepper%' THEN '1'
+	ELSE '0'
+	END AS pepper_flag
+
+FROM product
+
+
+
+
 <div align="center">-</div>
 
 #### JOIN
 1. Write a query that `INNER JOIN`s the `vendor` table to the `vendor_booth_assignments` table on the `vendor_id` field they both have in common, and sorts the result by `vendor_name`, then `market_date`.
 
+
+SELECT
+vendor.vendor_id,
+vendor_booth_assignments.booth_number,
+vendor_booth_assignments.market_date,
+vendor.vendor_name
+
+FROM vendor
+
+INNER JOIN 
+	vendor_booth_assignments
+	ON vendor.vendor_id = vendor_booth_assignments.vendor_id
+
+ORDER BY 
+	vendor.vendor_name,
+	vendor_booth_assignments.market_date
+
+
+
 ***
 
 ## Section 3:
@@ -157,10 +236,48 @@ Steps to complete this part of the assignment:
 
 #### AGGREGATE
 1. Write a query that determines how many times each vendor has rented a booth at the farmer’s market by counting the vendor booth assignments per `vendor_id`.
+
+
+
+	SELECT vendor_id, count(booth_number) AS booth_rentals
+	FROM vendor_booth_assignments
+	GROUP BY vendor_id
+
+
+
+
 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list of customers for them to give stickers to, sorted by last name, then first name.
 
 **HINT**: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword.
 
+
+SELECT
+	customer.customer_id,
+	customer.customer_first_name,
+	customer.customer_last_name,
+	sum(customer_purchases.quantity * customer_purchases.cost_to_customer_per_qty) AS total_spent
+
+FROM 
+	customer
+
+INNER JOIN customer_purchases
+		ON customer.customer_id = customer_purchases.customer_id
+
+
+GROUP BY 
+	customer.customer_id,
+	customer.customer_first_name,
+	customer.customer_last_name
+
+	HAVING total_spent > 2000
+
+	ORDER BY customer_last_name, customer_first_name
+
+
+
+
+
+
 <div align="center">-</div>
 
 #### Temp Table
@@ -171,6 +288,17 @@ Steps to complete this part of the assignment:
 To insert the new row use VALUES, specifying the value you want for each column:  
 `VALUES(col1,col2,col3,col4,col5)`
 
+
+CREATE TEMP TABLE temp_new_vendor AS 
+SELECT * 
+FROM vendor;
+
+
+INSERT INTO temp_new_vendor
+VALUES (10, 'Thomas Superfood Store', 'Fresh Focused Store', 'Thomas', 'Rosenthal')
+
+
+
 <div align="center">-</div>
 
 #### Date

02_activities/assignments/assignment1.sql

@@ -1,24 +1,37 @@
-/* ASSIGNMENT 1 */
+/* ASSIGNMENT 1 */ - MUBASHARA MALBARI
 /* SECTION 2 */
 
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
 
+SELECT *
+FROM customer
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
 
+SELECT *
+FROM customer
+ORDER BY customer_last_name, customer_first_name
+LIMIT 10
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 -- option 1
 
+SELECT *
+FROM customer_purchases
+WHERE product_id = 4
+OR product_id = 9
 
 -- option 2
 
+SELECT *
+FROM customer_purchases
+WHERE product_id IN (4, 9)
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -28,9 +41,15 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
 */
 -- option 1
 
+SELECT *, quantity * cost_to_customer_per_qty AS price
+FROM customer_purchases
+WHERE vendor_id >= 8 AND vendor_id <= 10
 
 -- option 2
 
+SELECT *, quantity * cost_to_customer_per_qty AS price
+FROM customer_purchases
+WHERE vendor_id BETWEEN 8 AND 10
 
 
 --CASE
@@ -40,18 +59,51 @@ columns and add a column called prod_qty_type_condensed that displays the word 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
 
 
+SELECT 
+product_id, product_name
+,CASE WHEN product_qty_type = 'unit' THEN 'unit'
+	ELSE 'bulk'
+	END AS product_qty_type_condensed
+
+FROM product
+
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
 
+SELECT 
+product_id, product_name
+,CASE WHEN product_qty_type = 'unit' THEN 'unit'
+	ELSE 'bulk'
+	END AS product_qty_type_condensed
+	,CASE WHEN product_name like '%pepper%' THEN '1'
+	ELSE '0'
+	END AS pepper_flag
+
+FROM product
 
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
 
 
+SELECT
+vendor.vendor_id,
+vendor_booth_assignments.booth_number,
+vendor_booth_assignments.market_date,
+vendor.vendor_name
+
+FROM vendor
+
+INNER JOIN 
+	vendor_booth_assignments
+	ON vendor.vendor_id = vendor_booth_assignments.vendor_id
+
+ORDER BY 
+	vendor.vendor_name,
+	vendor_booth_assignments.market_date
 
 
 /* SECTION 3 */
@@ -61,6 +113,11 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
 
 
+SELECT vendor_id, count(booth_number) AS booth_rentals
+	FROM vendor_booth_assignments
+	GROUP BY vendor_id
+
+
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
 sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
@@ -69,6 +126,29 @@ of customers for them to give stickers to, sorted by last name, then first name.
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
 
+SELECT
+	customer.customer_id,
+	customer.customer_first_name,
+	customer.customer_last_name,
+	sum(customer_purchases.quantity * customer_purchases.cost_to_customer_per_qty) AS total_spent
+
+FROM 
+	customer
+
+INNER JOIN customer_purchases
+		ON customer.customer_id = customer_purchases.customer_id
+
+
+GROUP BY 
+	customer.customer_id,
+	customer.customer_first_name,
+	customer.customer_last_name
+
+	HAVING total_spent > 2000
+
+	ORDER BY customer_last_name, customer_first_name
+
+
 
 --Temp Table
 /* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: 
@@ -84,6 +164,17 @@ VALUES(col1,col2,col3,col4,col5)
 
 
 
+CREATE TEMP TABLE temp_new_vendor AS 
+SELECT * 
+FROM vendor;
+
+
+INSERT INTO temp_new_vendor
+VALUES (10, 'Thomas Superfood Store', 'Fresh Focused Store', 'Thomas', 'Rosenthal')
+
+
+
+
 -- Date
 /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.