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Theorem Suggestion: Connected+ strongly paracompact => countable extent #1189
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I'm currently working on S129 and that's how I landed here. |
#990 has some partial results on S129 that you can refer to. |
The results can be strengthen to P18 (Lindelöf), https://mathoverflow.net/questions/433812/a-stronger-version-of-paracompactness is also a good reference. @pzjp |
True. It appears that every star-finite open cover of a connected space has to be (at most) countable. |
Yes you can post it right after that existing post (if you think the current answer is not complete) |
It would be good to have the "metric hedgehog" (as mentioned by Tyrone in comment to the mo post) as a space in pi-base. That's essentially the quotient of S129 (Wheel without its hub) obtained by collapsing the outer circle to a point. We should have both:
I am guessing the first one would be strongly paracompact. Now I am looking at S134 (Radial metric on the plane). Isn't that the same as the (second) metric hedgehog? |
The second is exactly S134. The first is embeddable in Euclidean plane |
If anyone of us plans to add one or more hedgehog spaces, I think it would be good to first create an issue to discuss the best presentation to choose for pi-base, which versions to add, names and so on. |
Theorem Suggestion
If a space is:
then it has countable extent P198.
Rationale
This theorem would demonstrate that no spaces satisfy the following search:
https://topology.pi-base.org/spaces?q=connected%2BStrongly+paracompact%2B%7EHas+countable+extent
Would also (eventually) resolve P145 for S129 and S134.
Proof
Let$C$ be a closed discrete subspace of a connected and strongly paracompact space $X$ . Take an open cover $\mathscr U=\{X\setminus A\}\cup\{U_a:a\in C\}$ where $U_a$ 's are disjoint open neighborhoods of the elements of $C$ . Let $\mathscr A$ be a star-finite refinement of $\mathscr U$ and for every $a\in C$ fix $E_a\in \mathscr A$ such that $a\in E_a$ . Clealry, $E_a\neq E_b$ for distinct $a,b\in C$ .$G=\{ \mathscr A, E\}$ where $(U,V)\in E$ whenever $U\neq V$ and $U\cap V\neq \emptyset$ . By the connectedness of $X$ and the fact that $\mathscr A$ is an open cover, $G$ is a connected graph and by star-finiteness every vertex is of finite degree.$n$ from the given one and the graph is a countable union over all distances). Hence $C$ is countable as well.
Consider a graph
A connected graph with all vertices of finite degree has to be countable (there are finitely many vertices at a distance at most
Should I make a self-answered entry on MathSE for this?
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