Assignment-1

02_activities/assignments/assignment1.sql

@@ -4,71 +4,128 @@
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
-
+SELECT *
+FROM customer;
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
-
-
+SELECT *
+FROM customer
+ORDER BY customer_last_name, customer_first_name
+LIMIT 10;
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 -- option 1
-
+SELECT * FROM customer_purchases
+WHERE product_id = 4
+OR product_id = 9;
 
 -- option 2
-
-
+SELECT * FROM customer_purchases
+WHERE product_id IN (4, 9);
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
 filtered by vendor IDs between 8 and 10 (inclusive) using either:
 	1.  two conditions using AND
 	2.  one condition using BETWEEN
 */
--- option 1
+-- option 1 X
+--ALTER TABLE customer_purchases ADD price AS (quantity*cost_to_customer_per_qty);
+SELECT *
+FROM customer_purchases
+WHERE  vendor_id  >=8 
+AND  vendor_id <= 10;
+--GROUP BY customer_id, product_id, vendor_id
 
 
 -- option 2
+SELECT 
+customer_id,
+product_id,
+vendor_id,
 
+SUM(quantity*cost_to_customer_per_qty) as price
 
+FROM customer_purchases
+WHERE  vendor_id BETWEEN 8 AND 10;
 
 --CASE
 /* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. 
 Using the product table, write a query that outputs the product_id and product_name
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
 
+SELECT product_id, product_name
+
+	,CASE 
+		WHEN product_qty_type = 'unit' THEN 'unit'
+		ELSE 'bulk'
+	END as prod_qty_type_condensed
+
+FROM product;
 
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
 
-
+SELECT product_id, product_name
+
+	,CASE 
+		WHEN product_qty_type = 'unit' THEN 'unit'
+		ELSE 'bulk'
+	END as prod_qty_type_condensed
+
+	,CASE 
+		WHEN product_name LIKE '%pepper%'
+			THEN '1'
+			ELSE '0'
+		END as pepper_flag
+
+FROM product;
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
 
+SELECT *
 
+FROM vendor INNER JOIN vendor_booth_assignments
+ON vendor.vendor_id = vendor_booth_assignments.vendor_id
 
+GROUP BY vendor_name, market_date;
 
 /* SECTION 3 */
 
 -- AGGREGATE
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
 
-
+SELECT vendor_id, COUNT (vendor_id) as num_of_rented
+FROM vendor_booth_assignments
+GROUP BY vendor_id;
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
 sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
 of customers for them to give stickers to, sorted by last name, then first name. 
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
+SELECT
+	c.customer_first_name, 
+	c.customer_last_name,
+	c.customer_id,
+	SUM (cp.quantity*cp.cost_to_customer_per_qty) AS total_spent
 
+FROM customer c
+LEFT JOIN customer_purchases cp
+	ON c.customer_id = cp.customer_id
+
+GROUP BY c.customer_first_name, c.customer_last_name, c.customer_id
+HAVING SUM (cp.quantity*cp.cost_to_customer_per_qty) > 2000
+ORDER BY c.customer_last_name, c.customer_first_name;
 
 --Temp Table
 /* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: 
@@ -82,19 +139,41 @@ When inserting the new vendor, you need to appropriately align the columns to be
 VALUES(col1,col2,col3,col4,col5) 
 */
 
+CREATE TABLE temp.new_vendor AS
+
+SELECT * FROM vendor;
 
+INSERT INTO temp.new_vendor
+VALUES(10, 'THomass Superfood Store', 'Fresh Focused', 'Thomas','Rosenthal')
+
+SELECT * FROM temp.new_vendor;
 
 -- Date
 /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
 
 HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
-and year are! */
-
+and year are! */ X
 
+SELECT 
+	customer_id,
+	strftime('%m', market_date) AS month,
+	strftime('%Y', market_date) AS year
 
+FROM customer_purchases
+
 /* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. 
 Remember that money spent is quantity*cost_to_customer_per_qty. 
 
 HINTS: you will need to AGGREGATE, GROUP BY, and filter...
 but remember, STRFTIME returns a STRING for your WHERE statement!! */
 
+SELECT  
+	customer_id,
+	SUM (quantity*cost_to_customer_per_qty) AS total_spent
+
+
+FROM customer_purchases
+WHERE strftime('%m', market_date) = '04'
+AND strftime('%Y', market_date) = '2022'
+
+GROUP BY customer_id

05_src/sql/assignment1.sqbpro

@@ -0,0 +1,24 @@
+<?xml version="1.0" encoding="UTF-8"?><sqlb_project><db path="assignment1.db" readonly="0" foreign_keys="0" case_sensitive_like="0" temp_store="0" wal_autocheckpoint="1000" synchronous="2"/><attached/><window><main_tabs open="structure browser pragmas query" current="3"/></window><tab_structure><column_width id="0" width="300"/><column_width id="1" width="0"/><column_width id="2" width="100"/><column_width id="3" width="7306"/><column_width id="4" width="0"/><expanded_item id="0" parent="1"/><expanded_item id="1" parent="1"/><expanded_item id="2" parent="1"/><expanded_item id="3" parent="1"/></tab_structure><tab_browse><table title="booth" custom_title="0" dock_id="2" table="4,5:mainbooth"/><dock_state state="000000ff00000000fd00000001000000020000000000000000fc0100000002fb000000160064006f0063006b00420072006f00770073006500310100000000ffffffff0000000000000000fb000000160064006f0063006b00420072006f00770073006500320100000000ffffffff0000010100ffffff000000000000000000000004000000040000000800000008fc00000000"/><default_encoding codec=""/><browse_table_settings><table schema="main" name="booth" show_row_id="0" encoding="" plot_x_axis="" unlock_view_pk="_rowid_" freeze_columns="0"><sort/><column_widths><column index="1" value="104"/><column index="2" value="125"/><column index="3" value="300"/><column index="4" value="83"/></column_widths><filter_values/><conditional_formats/><row_id_formats/><display_formats/><hidden_columns/><plot_y_axes/><global_filter/></table></browse_table_settings></tab_browse><tab_sql><sql name="assignment1.sql*" filename="/Users/Hiro/sql/02_activities/assignments/assignment1.sql">-- Reference to file &quot;/Users/Hiro/sql/02_activities/assignments/assignment1.sql&quot; (not supported by this version) --</sql><sql name="SQL 4">SELECT
+    c.customer_first_name, 
+    c.customer_last_name,
+    c.customer_id,
+    SUM(cp.quantity * cp.cost_to_customer_per_qty) AS total_spent
+FROM customer c
+LEFT JOIN customer_purchases cp
+    ON c.customer_id = cp.customer_id
+GROUP BY c.customer_first_name, c.customer_last_name, c.customer_id
+HAVING SUM(cp.quantity * cp.cost_to_customer_per_qty) &gt; 2000
+ORDER BY c.customer_last_name, c.customer_first_name;</sql><sql name="SQL 2">SELECT
+    c.customer_first_name, 
+    c.customer_last_name,
+    c.customer_id,
+    SUM(cp.quantity * cp.cost_to_customer_per_qty) AS total_spent
+FROM customer c
+LEFT JOIN customer_purchases cp
+    ON c.customer_id = cp.customer_id
+GROUP BY c.customer_first_name, c.customer_last_name, c.customer_id
+HAVING SUM(cp.quantity * cp.cost_to_customer_per_qty) &gt; 2000
+ORDER BY c.customer_last_name, c.customer_first_name;
+
+
+</sql><current_tab id="0"/></tab_sql></sqlb_project>

05_src/sql/farmersmarket.sqbpro

@@ -0,0 +1,138 @@
+<?xml version="1.0" encoding="UTF-8"?><sqlb_project><db path="farmersmarket.db" readonly="0" foreign_keys="1" case_sensitive_like="0" temp_store="0" wal_autocheckpoint="1000" synchronous="2"/><attached/><window><main_tabs open="structure browser pragmas query" current="3"/></window><tab_structure><column_width id="0" width="300"/><column_width id="1" width="0"/><column_width id="2" width="100"/><column_width id="3" width="7306"/><column_width id="4" width="0"/><expanded_item id="0" parent="1"/><expanded_item id="1" parent="1"/><expanded_item id="2" parent="1"/><expanded_item id="3" parent="1"/></tab_structure><tab_browse><table title="booth" custom_title="0" dock_id="1" table="4,5:mainbooth"/><dock_state state="000000ff00000000fd0000000100000002000001c30000021ffc0100000001fb000000160064006f0063006b00420072006f00770073006500310100000000000001c30000010a00ffffff000001c30000000000000004000000040000000800000008fc00000000"/><default_encoding codec=""/><browse_table_settings><table schema="main" name="booth" show_row_id="0" encoding="" plot_x_axis="" unlock_view_pk="_rowid_" freeze_columns="0"><sort/><column_widths><column index="1" value="104"/><column index="2" value="125"/><column index="3" value="300"/><column index="4" value="83"/></column_widths><filter_values/><conditional_formats/><row_id_formats/><display_formats/><hidden_columns/><plot_y_axes/><global_filter/></table></browse_table_settings></tab_browse><tab_sql><sql name="SQL 1*">-- SELECT 
+
+--selecting everything from customer
+SELECT * 
+FROM customer;
+
+-- add a static value
+SELECT 2025 as this_year, 'April' as this_month, customer_id
+FROM customer;
+
+-- add an order by + limit
+SELECT * 
+FROM customer
+ORDER BY customer_last_name
+LIMIT 10;
+
+--WHERE
+
+SELECT * FROM customer
+WHERE customer_id = 1
+AND customer_id = 2; 
+
+-- IN
+SELECT * From customer_purchases
+WHERE customer_id IN (3,4,5) -- only custmoer 3, 4, 5
+AND vendor_id IN (3,4,5); 
+
+-- LLIKE
+SELECT * FROM product
+WHERE product_name LIKE '%pepper%';
+
+-- customers with a last name starting with a
+SELECT * FROM customer
+WHERE customer_last_name LIKE 'a%';
+
+SELECT * FROM product
+WHERE product_size IS NULL
+OR product_size = '';
+
+</sql><sql name="SQL 2*">SELECT * 
+,CASE WHEN vendor_type = 'Fresh Focused'
+	THEN 'Wednesday'
+WHEN vendor_type = 'Prepared Foods'
+	THEN 'Thursday'
+ELSE 'Saturday'
+END as day_of_specialty
+--pie day, otherwise nothing
+,CASE WHEN vendor_name LIKE '%pie%'
+	THEN 'Wednesday'
+	END as only_pie_day
+,CASE WHEN vendor_name = &quot;Annie's Pies&quot;  -- double quote work, but not for all editors!
+	THEN 'annie is best'
+	END
+FROM vendor</sql><sql name="SQL 3*">--DISTINCT
+
+-- Without distinct 4421 rows oof various customer_id
+SELECT customer_id FROM customer_purchases;
+
+SELECT DISTINCT customer_id FROM customer_purchases
+
+-- without distinctio, only we/sad 150 tiems OVER
+SELECT * 
+FROM market_date_info;
+
+-- which vendor has sold product a customer 
+SELECT DISTINCT vendor_id
+FROM customer_purchases; -- 3 rows, vendor id 7, 8 4
+
+-- which vendor has sold products to a customer 
+SELECT DISTINCT vendor_id, product_id
+FROM customer_purchases; 
+
+-- which vencor has sold products to a customer and which product was it and to whom it was sold?
+SELECT DISTINCT vendor_id, customer_id, product_id
+FROM customer_purchases
+
+SELECT * 
+,CASE WHEN vendor_type = 'Fresh Focused'
+	THEN 'Wednesday'
+WHEN vendor_type = 'Prepared Foods'
+	THEN 'Thursday'
+ELSE 'Saturday'
+END as day_of_specialty
+--pie day, otherwise nothing
+,CASE WHEN vendor_name LIKE '%pie%'
+	THEN 'Wednesday'
+	END as only_pie_day
+,CASE WHEN vendor_name = &quot;Annie's Pies&quot;  -- double quote work, but not for all editors!
+	THEN 'annie is best'
+	END as annie_is_king
+FROM vendor
+
+</sql><sql name="SQL 4*">-- INNER JOIN
+
+-- get prodcut names along customer_purchases
+SELECT 
+product_name, 
+market_date,
+customer_id, 
+product_id, 
+customer_purchases.product_id
+
+FROM customer_purchases
+INNER JOIN product
+	ON customer_purchases.product_id = product.product_id</sql><sql name="SQL 5*">/* get product names alongside customer_purchases...only products that a customer has purchased will be present */
+SELECT 
+product_name, -- coming from product
+vendor_id, -- coming from cp...below
+market_date,
+customer_id,
+customer_purchases.product_id
+
+FROM customer_purchases
+INNER JOIN product
+	ON customer_purchases.product_id = product.product_id;
+
+/* which vendor has sold products to a customer AND which product was it AND to whom was it sold ? */
+SELECT DISTINCT vendor_id, 
+product_id, 
+--customer_id -- this is dissatisfying...let's have a name!
+customer_first_name,
+customer_last_name
+
+FROM customer_purchases as cp
+INNER JOIN customer as c
+	ON cp.customer_id = c.customer_id</sql><sql name="SQL 6*">-- LEFT JOIN
+
+-- there are produts being bought, but not have not?
+SELECT
+p.product_id, cp.product_id, 
+cp.*--all colums in cp TABLE
+
+FROM product p
+LEFT JOIN customer_purchases cp
+	ON p.product_id = cp.product_id
+
+</sql><sql name="SQL 7*">SELECT DISTINCT
+p.product_id, product_name, </sql><sql name="SQL 8"></sql><current_tab id="5"/></tab_sql></sqlb_project>