Possible bug in ipix calculation? #1
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Above unchanged code (i.e. without the commenting out) gives: 2 = xy2pix(1,1,1,1) 13 = xy2pix(1,1,1,12) After edits (i.e. %ipix = ipix+1;) it gives: 1 = xy2pix(1,1,1,1) 12 = xy2pix(1,1,1,1)
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Thanks for bringing it up! |
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@pochoi |
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Above unchanged code (i.e. without the commenting out) gives:
2 = xy2pix(1,1,1,1)
13 = xy2pix(1,1,1,12)
After edits (i.e. %ipix = ipix+1;) it gives:
1 = xy2pix(1,1,1,1)
12 = xy2pix(1,1,1,12)