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ARQUIVOS COM RESOLUÇÃO DOS EXERCICIOS #20
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#LOJA DE TINTAS: | ||
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tamanho = float(input("QUANTOS METROS QUADRADOS TEM A ÁREA A SER PINTADA? ")) | ||
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metroQuadradoPorLitro = 3 | ||
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litrosNecessarios = tamanho / metroQuadradoPorLitro | ||
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lataLitros = 18 | ||
lataPreco = 80 | ||
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latasNecessarias = litrosNecessarios / lataLitros | ||
precoNecessario = lataPreco * latasNecessarias | ||
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print("Latas necessárias abaixo.") | ||
print(int(latasNecessarias)) | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Não está errado, mas porque você converteu latasNecessárias para inteiro ao imprimir? |
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print("Preço necessário abaixo.") | ||
print(float(precoNecessario)) |
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tamanho = float(input()) | ||
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litroCobertura_a_cadaMetro = 6 #DE UM LITRO A CADA SEIS METROS | ||
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#INFORMAÇÕES DAS LATAS | ||
litroLata = 18 | ||
preçoLata = 80 | ||
preçoGalão = 25 | ||
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#comprar apenas latas de 18 litros; | ||
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litrosNecessarios = tamanho/litroCobertura_a_cadaMetro | ||
latasNecessarias = litrosNecessarios/litroLata | ||
preçoNecessario = preçoLata * latasNecessarias | ||
print("Latas necessárias: ") | ||
print(int(latasNecessarias)) | ||
print("Valor necessários: ") | ||
print(float(preçoNecessario)) | ||
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#3. Faça um programa, com uma função que necessite de três argumentos, e que forneça a soma desses três argumentos. | ||
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def calcular_soma(a, b, c): | ||
soma = a + b + c | ||
return soma | ||
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num1 = float(input("Primeiro número: ")) | ||
num2 = float(input("Segundo número: ")) | ||
num3 = float(input("Terceiro número: ")) | ||
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resultado = calcular_soma(num1, num2, num3) | ||
print(f"A soma dos três números é: {resultado}") |
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Quase. Mas há um porém: Se o resultado da divisão não for exato, por exemplo 35/18, o resultado será 1 e faltará tinta.