xcswitch

Switch between Xcode versions but keeping current Xcode version as /Applications/Xcode.app

All other versions will remain under /Applications with their corresponding versions appended to its name.

~ % ls -1d /Applications/Xcode*
/Applications/Xcode.app         -- Current Version is 8.3.3
/Applications/Xcode8.2.1.app    -- other Xcode's
/Applications/Xcode9.0.app

Why not 'xcode-select'?

That's the official and correct way of doing this, but I found out that some older projects still have (or generate) map files that depend on Applications/Xcode.app being the Xcode location.

If you xcode-select and point it to, for example, /Applications/Xcode8.2.1.app the build will probably fail and/or you'll spend 100 hours trying to figure out why things don't work as they should. Trust me, it happened before...

Usage

When running the script without any arguments, it prints the current version and lists all other Xcode versions you have installed under /Applications.

Note: when creating the list, the script strips out /Applications/Xcode and .app from the directory names, so you'll only see the version. This assumes you're using a similar naming convention as shown above. i.e. Xcode8.2.1.app, Xcode9.0.app, etc.

~ % ./xcswitch.sh
Xcode switcher -- Currently: [8.3.3]

1) 8.2.1
2) 9.0
Select Xcode version to use: (CTRL+C to quit)

If you know the version you want to switch to, just type it as argument.

~ % ./xcswitch.sh 9.0
Xcode switcher -- Currently: [8.3.3]

Switching from: [8.3.3] - to: [9.0]
...
Password:
Double check versions below:
Xcode 9.0
Build version 9A235
Apple Swift version 4.0 (swiftlang-900.0.65 clang-900.0.37)
Target: x86_64-apple-macosx10.9

You might be asked for your user password as the script required sudo privileges.