Oppgave 2

assignments/main.py

@@ -0,0 +1,92 @@
+
+def read_file(file_name):
+    """
+    Denne funksjonen får et filnavn som argument og skal gi
+    tilbake en liste av tekststrenger som representerer linjene i filen.
+    """
+    liste=[]
+    with open(file_name, 'r') as file:
+        lines = file.readlines()
+        for line in lines:
+            liste.append(line)
+        print(liste)
+    file.close()
+    return liste
+
+
+liste1 = read_file('small.txt')
+
+
+def lines_to_words(lines):
+    new_list = []
+    for word in lines:
+        x = word.split()
+        new_list.append(x)
+    flattened = [val for sublist in new_list for val in sublist]
+    flattened_2 = list(map(str.lower,flattened))
+    flattened_fin = [i.strip('!') for i in flattened_2]
+
+
+    print(flattened_fin)
+    return flattened_fin
+
+lines_to_words(liste1)
+
+
+list2 = lines_to_words(liste1)
+
+def compute_frequency(words):
+    counts = dict()
+    for word in words:
+        if word in counts:
+            counts[word] +=1
+        else:
+            counts[word] = 1
+    print(counts)
+    return counts
+
+compute_frequency(list2)
+x = compute_frequency(list2)
+
+
+def remove_filler_words(frequency_table):
+    FILLER_WORDs = ['er', 'og',]
+    for element in FILLER_WORDs:
+        if element in frequency_table:
+            frequency_table.pop(str(element))
+        else:
+            pass
+    print(frequency_table)
+    return frequency_table
+
+remove_filler_words(x)
+o = remove_filler_words(x)
+
+v = list(remove_filler_words((x)).items())
+print(v)
+
+
+def largest_pair(par_1, par_2):
+    if par_1[1] > par_2[1]:
+        print(str[par_1[0]] + ' er størst')
+    elif par_1[1] < par_2[1]:
+        print(str[par_2[0]] + ' er størst')
+    elif par_1[1] == par_2[1]:
+        print('Begge parene er like store')
+    return
+
+largest_pair(v[0], v[1])
+
+def find_most_frequent(frequency_table):
+    track = {}
+    for key, value in frequency_table.items():
+        if value not in track:
+            track[value] =0
+        else:
+            track[value] +=1
+    print(max(track, key=track.get))
+
+find_most_frequent(o)
+
+
+

assignments/small.txt

@@ -0,0 +1,3 @@
+Det er
+bare
+noen få ord her!