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Binary file added 02_activities/assignments/Assignment-two.db
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193 changes: 193 additions & 0 deletions 02_activities/assignments/assignment2.sql
Original file line number Diff line number Diff line change
Expand Up @@ -20,29 +20,116 @@ The `||` values concatenate the columns into strings.
Edit the appropriate columns -- you're making two edits -- and the NULL rows will be fixed.
All the other rows will remain the same.) */

SELECT
product_name || ', ' ||
COALESCE(product_size, '') || ' (' ||
COALESCE(product_qty_type, 'unit') || ')' AS product_details
FROM product;


--Windowed Functions
/* 1. Write a query that selects from the customer_purchases table and numbers each customer’s
visits to the farmer’s market (labeling each market date with a different number).
Each customer’s first visit is labeled 1, second visit is labeled 2, etc.


You can either display all rows in the customer_purchases table, with the counter changing on
each new market date for each customer, or select only the unique market dates per customer
(without purchase details) and number those visits.
HINT: One of these approaches uses ROW_NUMBER() and one uses DENSE_RANK(). */

--use ROW_NUMBER()
SELECT
customer_id,
market_date,
ROW_NUMBER() OVER (
PARTITION BY customer_id
ORDER BY market_date
) AS visit_number
FROM customer_purchases;

--use DENSE_RANK (it wont skip any number)
SELECT
customer_id,
market_date,
DENSE_RANK() OVER (
PARTITION BY customer_id
ORDER BY market_date
) AS visit_number
FROM customer_purchases;



/* 2. Reverse the numbering of the query from a part so each customer’s most recent visit is labeled 1,
then write another query that uses this one as a subquery (or temp table) and filters the results to
only the customer’s most recent visit. */

--reverse using dense_rank
SELECT
customer_id,
market_date,
DENSE_RANK() OVER (
PARTITION BY customer_id
ORDER BY market_date DESC
) AS reverse_visit_number
FROM customer_purchases;

--reverse using row_number
SELECT
customer_id,
market_date,
ROW_NUMBER() OVER (
PARTITION BY customer_id
ORDER BY market_date DESC
) AS reverse_visit_number
FROM customer_purchases;

-- most recent visit using dense_rank
SELECT
customer_id,
market_date
FROM (
SELECT
customer_id,
market_date,
DENSE_RANK() OVER (
PARTITION BY customer_id
ORDER BY market_date DESC
) AS reverse_visit_number
FROM customer_purchases
) AS customer_most_rencent_visit
WHERE reverse_visit_number = 1;

--most recent using row_number
SELECT
customer_id,
market_date
FROM (
SELECT
customer_id,
market_date,
ROW_NUMBER() OVER (
PARTITION BY customer_id
ORDER BY market_date DESC
) AS reverse_visit_number
FROM customer_purchases
) AS customer_most_recent_visit
WHERE reverse_visit_number = 1;



/* 3. Using a COUNT() window function, include a value along with each row of the
customer_purchases table that indicates how many different times that customer has purchased that product_id. */

SELECT
customer_id,
product_id,
quantity,
market_date,
COUNT(*) OVER (
PARTITION BY customer_id, product_id
) AS times_purchased
FROM customer_purchases;


-- String manipulations
Expand All @@ -57,10 +144,24 @@ Remove any trailing or leading whitespaces. Don't just use a case statement for

Hint: you might need to use INSTR(product_name,'-') to find the hyphens. INSTR will help split the column. */

SELECT
product_name,
CASE
WHEN INSTR(product_name, '-') > 0 THEN
TRIM(SUBSTR(product_name, INSTR(product_name, '-') + 1))
ELSE
NULL
END AS description
FROM product;


/* 2. Filter the query to show any product_size value that contain a number with REGEXP. */

SELECT
product_name,
product_size
FROM product
WHERE product_size REGEXP '[0-9]';


-- UNION
Expand All @@ -73,7 +174,47 @@ HINT: There are a possibly a few ways to do this query, but if you're struggling
3) Query the second temp table twice, once for the best day, once for the worst day,
with a UNION binding them. */

-- 1. create temp sales table
DROP TABLE IF EXISTS temp_sales_by_date;
CREATE TEMP TABLE temp_sales_by_date AS
SELECT
market_date,
SUM(quantity * original_price) AS total_sales
FROM vendor_inventory
GROUP BY market_date;

--check
select * from temp_sales_by_date;

--2. Second temp table for best and worse day
DROP TABLE IF EXISTS temp_ranked_sales;
CREATE TEMP TABLE temp_ranked_sales AS
SELECT
market_date,
total_sales,
RANK() OVER (ORDER BY total_sales DESC) AS best_day,
RANK() OVER (ORDER BY total_sales ASC) AS worst_day
FROM temp_sales_by_date;

--check
SELECT * FROM temp_ranked_sales;

--3 use union
SELECT
market_date,
total_sales,
'Best Day' AS day_type
FROM temp_ranked_sales
WHERE best_day = 1

UNION

SELECT
market_date,
total_sales,
'Worst Day' AS day_type
FROM temp_ranked_sales
WHERE worst_day= 1;


/* SECTION 3 */
Expand All @@ -89,6 +230,18 @@ Think a bit about the row counts: how many distinct vendors, product names are t
How many customers are there (y).
Before your final group by you should have the product of those two queries (x*y). */

SELECT
v.vendor_name,
p.product_name,
SUM(5 * vi.original_price) AS total_revenue
FROM
vendor_inventory vi
JOIN vendor v ON vi.vendor_id = v.vendor_id
JOIN product p ON vi.product_id = p.product_id
CROSS JOIN customer c
GROUP BY
v.vendor_name,
p.product_name;


-- INSERT
Expand All @@ -97,18 +250,45 @@ This table will contain only products where the `product_qty_type = 'unit'`.
It should use all of the columns from the product table, as well as a new column for the `CURRENT_TIMESTAMP`.
Name the timestamp column `snapshot_timestamp`. */

DROP TABLE IF EXISTS product_units;
CREATE TABLE product_units AS
SELECT
*,
CURRENT_TIMESTAMP AS snapshot_timestamp
FROM product
WHERE product_qty_type = 'unit';

INSERT INTO product_units (product_id, product_name, product_size, product_qty_type, snapshot_timestamp)
SELECT
product_id,
product_name,
product_size,
product_qty_type,
CURRENT_TIMESTAMP
FROM product
WHERE product_qty_type = 'unit';


/*2. Using `INSERT`, add a new row to the product_units table (with an updated timestamp).
This can be any product you desire (e.g. add another record for Apple Pie). */

INSERT INTO product_units (
product_id,
product_name,
product_size,
product_qty_type,
snapshot_timestamp
)
VALUES (88, 'Chocolate Fudge Cake', '10"', 'unit', CURRENT_TIMESTAMP);


-- DELETE
/* 1. Delete the older record for the whatever product you added.

HINT: If you don't specify a WHERE clause, you are going to have a bad time.*/

DELETE FROM product_units
WHERE product_name = 'Chocolate Fudge Cake';


-- UPDATE
Expand All @@ -128,6 +308,19 @@ Finally, make sure you have a WHERE statement to update the right row,
you'll need to use product_units.product_id to refer to the correct row within the product_units table.
When you have all of these components, you can run the update statement. */

--add new column
ALTER TABLE product_units
ADD COLUMN current_quantity INT;

UPDATE product_units
SET current_quantity = COALESCE((
SELECT vi.quantity
FROM vendor_inventory vi
WHERE vi.product_id = product_units.product_id
), 0);

select * from product_units;




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