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| 1 | +//math, FFT, d&c |
| 2 | +//https://www.hackerrank.com/contests/w6/challenges/best-spot/editorial |
| 3 | +#include <stdio.h> |
| 4 | +#include <math.h> |
| 5 | +#include <vector> |
| 6 | +#include <complex> |
| 7 | +#define cpd complex<double> |
| 8 | +using namespace std; |
| 9 | +const double PI = acos(-1); |
| 10 | +int R, C, H, W; |
| 11 | +int sqx[501][501], sqy; |
| 12 | +void FFT(vector<cpd > &F, vector<cpd > &A, cpd w) { |
| 13 | + if (A.size() == 1) F = A; |
| 14 | + else { |
| 15 | + int n = A.size(); |
| 16 | + vector<cpd > a[2], f[2]; |
| 17 | + for (int i = 0; i < n; ++i) a[i & 1].push_back(A[i]); |
| 18 | + F.resize(n); n >>= 1; |
| 19 | + FFT(f[0], a[0], w*w); FFT(f[1], a[1], w*w); |
| 20 | + cpd x = 1; |
| 21 | + for (int i = 0; i < n; ++i) { |
| 22 | + cpd odd = f[1][i] * x; |
| 23 | + F[i] = f[0][i] + odd; |
| 24 | + F[i + n] = f[0][i] - odd; |
| 25 | + x *= w; |
| 26 | + } |
| 27 | + } |
| 28 | +} |
| 29 | +int main() { |
| 30 | + int i, j; |
| 31 | + int RC, p; |
| 32 | + for (scanf("%d%d", &R, &C), RC = R * C, p = 1; p < RC + RC; p += p); |
| 33 | + vector<cpd > h(p), ps(p); |
| 34 | + int ix = 0; |
| 35 | + for (i = 1; i <= R; ++i) { |
| 36 | + for (j = 1; j <= C; ++j,++ix) { |
| 37 | + scanf("%d",sqx[i]+j); |
| 38 | + h[ix] = h[ix + RC] = sqx[i][j]; |
| 39 | + sqx[i][j] *= sqx[i][j]; |
| 40 | + sqx[i][j] += sqx[i][j - 1] + sqx[i - 1][j] - sqx[i - 1][j - 1]; |
| 41 | + } |
| 42 | + } |
| 43 | + for (scanf("%d%d", &H, &W), i = 1,ix=RC; i <= H; ++i,ix-=C) { |
| 44 | + for (j = 1; j <= W; ++j) { |
| 45 | + int height; scanf("%d",&height); |
| 46 | + ps[ix - j] = height; |
| 47 | + sqy += height * height; |
| 48 | + } |
| 49 | + } |
| 50 | + double theta = (PI + PI) / p; |
| 51 | + cpd w(cos(theta), sin(theta)); |
| 52 | + FFT(h, h, w); FFT(ps, ps, w); |
| 53 | + for (i = 0; i < p; ++i) h[i] *= ps[i]; |
| 54 | + w = {cos(-theta),sin(-theta)}; |
| 55 | + FFT(h, h, w); |
| 56 | + int ans = -1; |
| 57 | + int r, c; |
| 58 | + for (i = 1,ix=RC-1; i <= R-H+1; ++i,ix+=C) { |
| 59 | + for (j = 1; j <= C-W+1; ++j) { |
| 60 | + double coef = h[ix+j-1].real()/p; |
| 61 | + coef += coef > 0 ? 0.5 : -0.5; |
| 62 | + int xy = coef; |
| 63 | + int sum = sqx[i + H-1][j + W-1]-sqx[i-1][j+W-1] |
| 64 | + -sqx[i+H-1][j-1]+sqx[i-1][j-1]; |
| 65 | + sum += sqy - xy - xy; |
| 66 | + if (ans<0 || ans>sum) { |
| 67 | + ans = sum; |
| 68 | + r = i, c = j; |
| 69 | + } |
| 70 | + } |
| 71 | + } |
| 72 | + printf("%d\n%d %d",ans,r,c); |
| 73 | + return 0; |
| 74 | +} |
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