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Unit 5 Session 1 (Click for link to problem statements)
TIP102 Unit 5 Session 1 Standard (Click for link to problem statements)
TIP102 Unit 5 Session 1 Advanced (Click for link to problem statements)
- 💡 Difficulty: Medium
- ⏰ Time to complete: 10-15 mins
- 🛠️ Topics: Classes, Linked List, Recursion
Understand what the interviewer is asking for by using test cases and questions about the problem.
- Established a set (2-3) of test cases to verify their own solution later.
- Established a set (1-2) of edge cases to verify their solution handles complexities.
- Have fully understood the problem and have no clarifying questions.
- Have you verified any Time/Space Constraints for this problem?
- What is the task?
- Implement a function
get_place()
to determine the position of a player in the race based on how many players are ahead of them.
- Implement a function
HAPPY CASE
Input: my_player = Player("Luigi", "Super Blooper", mario)
Output: 3
Explanation: Luigi is third in the race, with Mario and Peach ahead of him.
EDGE CASE
Input: my_player = Player("Peach", "Daytripper")
Output: 1
Explanation: Peach is first in the race, with no one ahead of her.
Match what this problem looks like to known categories of problems, e.g. Linked List or Dynamic Programming, and strategies or patterns in those categories.
For linked-list-like traversal problems, we want to consider the following approaches:
- Iteratively move through the
ahead
links until reaching the player at the front. - Count the number of steps taken to determine the rank.
Plan the solution with appropriate visualizations and pseudocode.
General Idea: Traverse through the linked list structure by following the ahead
attribute and counting the number of players ahead of my_player
.
1) Create a function `get_place(my_player)` that initializes `place` to 1.
2) Set `current` to `my_player`.
3) While `current.ahead` is not None, increment `place` by 1 and move `current` to `current.ahead`.
4) Return `place` after the loop.
- Forgetting to initialize
place
to 1 since the player is at least in some position. - Not correctly traversing the
ahead
links.
Implement the code to solve the algorithm.
def get_place(my_player):
place = 1 # Start counting from 1 as the player is at least in some place
current = my_player
while current.ahead:
place += 1
current = current.ahead
return place
Review the code by running specific example(s) and recording values (watchlist) of your code's variables along the way.
Trace through your code with the following input:
- my_player = luigi
- Verify that the output is 3 since Luigi has two players ahead of him.
- my_player = peach
- Verify that the output is 1 since Peach has no one ahead of her.
Evaluate the performance of your algorithm and state any strong/weak or future potential work.
- Time Complexity: O(N) where N is the number of players ahead of my_player.
- Space Complexity: O(1) as we only use a few variables to store state during the traversal."