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Popular Song Pairs
kyra-ptn edited this page Aug 11, 2024
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Unit 2 Session 1 (Click for link to problem statements)
Understand what the interviewer is asking for by using test cases and questions about the problem.
-
Q: What is the problem asking for?
- A: The problem asks to return the number of popular song pairs in an array of integers where a pair
(i, j)
is considered popular if the songs have the same popularity score andi < j
.
- A: The problem asks to return the number of popular song pairs in an array of integers where a pair
-
Q: What are the inputs?
- A: An array
popularity_scores
of integers representing the popularity scores of songs.
- A: An array
-
Q: What are the outputs?
- A: An integer representing the number of popular song pairs.
-
Q: Are there any constraints on the values in the array?
- A: The values can be any integers.
Plan the solution with appropriate visualizations and pseudocode.
General Idea: Use a dictionary to count occurrences of each popularity score and then calculate the number of pairs using combination formula.
1) Initialize an empty dictionary `score_count` to count occurrences of each popularity score.
2) Iterate through the `popularity_scores` array.
- For each score, update its count in the `score_count` dictionary.
3) Initialize a variable `popular_pairs` to 0.
4) Iterate through the values in the `score_count` dictionary.
- For each count greater than 1, add the number of pairs `(count * (count - 1)) // 2` to `popular_pairs`.
5) Return the value of `popular_pairs`.
- Ensure that the counts are correctly calculated.
- Handle cases where no popular pairs exist by returning 0.
def num_popular_pairs(popularity_scores):
# Step 1: Count occurrences of each score
score_count = {}
for score in popularity_scores:
if score in score_count:
score_count[score] += 1
else:
score_count[score] = 1
# Step 2: Calculate the number of popular pairs
popular_pairs = 0
for count in score_count.values():
if count > 1:
popular_pairs += (count * (count - 1)) // 2
return popular_pairs